jiangchengfeiyi-xiaochengxu/node_modules/mathjs/lib/cjs/function/probability/lgamma.js
2025-01-02 11:13:50 +08:00

143 lines
4.7 KiB
JavaScript

"use strict";
Object.defineProperty(exports, "__esModule", {
value: true
});
exports.createLgamma = void 0;
var _index = require("../../plain/number/index.js");
var _factory = require("../../utils/factory.js");
var _number = require("../../utils/number.js");
/* eslint-disable no-loss-of-precision */
// References
// ----------
// [1] Hare, "Computing the Principal Branch of log-Gamma", Journal of Algorithms, 1997.
// [2] https://math.stackexchange.com/questions/1338753/how-do-i-calculate-values-for-gamma-function-with-complex-arguments
const name = 'lgamma';
const dependencies = ['Complex', 'typed'];
const createLgamma = exports.createLgamma = /* #__PURE__ */(0, _factory.factory)(name, dependencies, _ref => {
let {
Complex,
typed
} = _ref;
// Stirling series is non-convergent, we need to use the recurrence `lgamma(z) = lgamma(z+1) - log z` to get
// sufficient accuracy.
//
// These two values are copied from Scipy implementation:
// https://github.com/scipy/scipy/blob/v1.8.0/scipy/special/_loggamma.pxd#L37
const SMALL_RE = 7;
const SMALL_IM = 7;
/**
* The coefficients are B[2*n]/(2*n*(2*n - 1)) where B[2*n] is the (2*n)th Bernoulli number. See (1.1) in [1].
*
* If you cannot access the paper, can also get these values from the formula in [2].
*
* 1 / 12 = 0.00833333333333333333333333333333
* 1 / 360 = 0.00277777777777777777777777777778
* ...
* 3617 / 133400 = 0.02955065359477124183006535947712
*/
const coeffs = [-2.955065359477124183e-2, 6.4102564102564102564e-3, -1.9175269175269175269e-3, 8.4175084175084175084e-4, -5.952380952380952381e-4, 7.9365079365079365079e-4, -2.7777777777777777778e-3, 8.3333333333333333333e-2];
/**
* Logarithm of the gamma function for real, positive numbers and complex numbers,
* using Lanczos approximation for numbers and Stirling series for complex numbers.
*
* Syntax:
*
* math.lgamma(n)
*
* Examples:
*
* math.lgamma(5) // returns 3.178053830347945
* math.lgamma(0) // returns Infinity
* math.lgamma(-0.5) // returns NaN
* math.lgamma(math.i) // returns -0.6509231993018536 - 1.8724366472624294i
*
* See also:
*
* gamma
*
* @param {number | Complex} n A real or complex number
* @return {number | Complex} The log gamma of `n`
*/
return typed(name, {
number: _index.lgammaNumber,
Complex: lgammaComplex,
BigNumber: function () {
throw new Error("mathjs doesn't yet provide an implementation of the algorithm lgamma for BigNumber");
}
});
function lgammaComplex(n) {
const TWOPI = 6.2831853071795864769252842; // 2*pi
const LOGPI = 1.1447298858494001741434262; // log(pi)
const REFLECTION = 0.1;
if (n.isNaN()) {
return new Complex(NaN, NaN);
} else if (n.im === 0) {
return new Complex((0, _index.lgammaNumber)(n.re), 0);
} else if (n.re >= SMALL_RE || Math.abs(n.im) >= SMALL_IM) {
return lgammaStirling(n);
} else if (n.re <= REFLECTION) {
// Reflection formula. see Proposition 3.1 in [1]
const tmp = (0, _number.copysign)(TWOPI, n.im) * Math.floor(0.5 * n.re + 0.25);
const a = n.mul(Math.PI).sin().log();
const b = lgammaComplex(new Complex(1 - n.re, -n.im));
return new Complex(LOGPI, tmp).sub(a).sub(b);
} else if (n.im >= 0) {
return lgammaRecurrence(n);
} else {
return lgammaRecurrence(n.conjugate()).conjugate();
}
}
function lgammaStirling(z) {
// formula ref in [2]
// computation ref:
// https://github.com/scipy/scipy/blob/v1.8.0/scipy/special/_loggamma.pxd#L101
// left part
// x (log(x) - 1) + 1/2 (log(2PI) - log(x))
// => (x - 0.5) * log(x) - x + log(2PI) / 2
const leftPart = z.sub(0.5).mul(z.log()).sub(z).add(_index.lnSqrt2PI);
// right part
const rz = new Complex(1, 0).div(z);
const rzz = rz.div(z);
let a = coeffs[0];
let b = coeffs[1];
const r = 2 * rzz.re;
const s = rzz.re * rzz.re + rzz.im * rzz.im;
for (let i = 2; i < 8; i++) {
const tmp = b;
b = -s * a + coeffs[i];
a = r * a + tmp;
}
const rightPart = rz.mul(rzz.mul(a).add(b));
// plus left and right
return leftPart.add(rightPart);
}
function lgammaRecurrence(z) {
// computation ref:
// https://github.com/scipy/scipy/blob/v1.8.0/scipy/special/_loggamma.pxd#L78
let signflips = 0;
let sb = 0;
let shiftprod = z;
z = z.add(1);
while (z.re <= SMALL_RE) {
shiftprod = shiftprod.mul(z);
const nsb = shiftprod.im < 0 ? 1 : 0;
if (nsb !== 0 && sb === 0) signflips++;
sb = nsb;
z = z.add(1);
}
return lgammaStirling(z).sub(shiftprod.log()).sub(new Complex(0, signflips * 2 * Math.PI * 1));
}
});