jiangchengfeiyi-xiaochengxu/node_modules/mathjs/lib/cjs/function/algebra/solver/usolve.js

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2025-01-02 03:13:50 +00:00
"use strict";
Object.defineProperty(exports, "__esModule", {
value: true
});
exports.createUsolve = void 0;
var _factory = require("../../../utils/factory.js");
var _solveValidation = require("./utils/solveValidation.js");
const name = 'usolve';
const dependencies = ['typed', 'matrix', 'divideScalar', 'multiplyScalar', 'subtractScalar', 'equalScalar', 'DenseMatrix'];
const createUsolve = exports.createUsolve = /* #__PURE__ */(0, _factory.factory)(name, dependencies, _ref => {
let {
typed,
matrix,
divideScalar,
multiplyScalar,
subtractScalar,
equalScalar,
DenseMatrix
} = _ref;
const solveValidation = (0, _solveValidation.createSolveValidation)({
DenseMatrix
});
/**
* Finds one solution of a linear equation system by backward substitution. Matrix must be an upper triangular matrix. Throws an error if there's no solution.
*
* `U * x = b`
*
* Syntax:
*
* math.usolve(U, b)
*
* Examples:
*
* const a = [[-2, 3], [2, 1]]
* const b = [11, 9]
* const x = usolve(a, b) // [[8], [9]]
*
* See also:
*
* usolveAll, lup, slu, usolve, lusolve
*
* @param {Matrix, Array} U A N x N matrix or array (U)
* @param {Matrix, Array} b A column vector with the b values
*
* @return {DenseMatrix | Array} A column vector with the linear system solution (x)
*/
return typed(name, {
'SparseMatrix, Array | Matrix': function (m, b) {
return _sparseBackwardSubstitution(m, b);
},
'DenseMatrix, Array | Matrix': function (m, b) {
return _denseBackwardSubstitution(m, b);
},
'Array, Array | Matrix': function (a, b) {
const m = matrix(a);
const r = _denseBackwardSubstitution(m, b);
return r.valueOf();
}
});
function _denseBackwardSubstitution(m, b) {
// make b into a column vector
b = solveValidation(m, b, true);
const bdata = b._data;
const rows = m._size[0];
const columns = m._size[1];
// result
const x = [];
const mdata = m._data;
// loop columns backwards
for (let j = columns - 1; j >= 0; j--) {
// b[j]
const bj = bdata[j][0] || 0;
// x[j]
let xj;
if (!equalScalar(bj, 0)) {
// value at [j, j]
const vjj = mdata[j][j];
if (equalScalar(vjj, 0)) {
// system cannot be solved
throw new Error('Linear system cannot be solved since matrix is singular');
}
xj = divideScalar(bj, vjj);
// loop rows
for (let i = j - 1; i >= 0; i--) {
// update copy of b
bdata[i] = [subtractScalar(bdata[i][0] || 0, multiplyScalar(xj, mdata[i][j]))];
}
} else {
// zero value at j
xj = 0;
}
// update x
x[j] = [xj];
}
return new DenseMatrix({
data: x,
size: [rows, 1]
});
}
function _sparseBackwardSubstitution(m, b) {
// make b into a column vector
b = solveValidation(m, b, true);
const bdata = b._data;
const rows = m._size[0];
const columns = m._size[1];
const values = m._values;
const index = m._index;
const ptr = m._ptr;
// result
const x = [];
// loop columns backwards
for (let j = columns - 1; j >= 0; j--) {
const bj = bdata[j][0] || 0;
if (!equalScalar(bj, 0)) {
// non-degenerate row, find solution
let vjj = 0;
// upper triangular matrix values & index (column j)
const jValues = [];
const jIndices = [];
// first & last indeces in column
const firstIndex = ptr[j];
const lastIndex = ptr[j + 1];
// values in column, find value at [j, j], loop backwards
for (let k = lastIndex - 1; k >= firstIndex; k--) {
const i = index[k];
// check row (rows are not sorted!)
if (i === j) {
vjj = values[k];
} else if (i < j) {
// store upper triangular
jValues.push(values[k]);
jIndices.push(i);
}
}
// at this point we must have a value in vjj
if (equalScalar(vjj, 0)) {
throw new Error('Linear system cannot be solved since matrix is singular');
}
const xj = divideScalar(bj, vjj);
for (let k = 0, lastIndex = jIndices.length; k < lastIndex; k++) {
const i = jIndices[k];
bdata[i] = [subtractScalar(bdata[i][0], multiplyScalar(xj, jValues[k]))];
}
x[j] = [xj];
} else {
// degenerate row, we can choose any value
x[j] = [0];
}
}
return new DenseMatrix({
data: x,
size: [rows, 1]
});
}
});